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tanyakisilova
@tanyakisilova
August 2022
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розвяжіть рівняння cos2x - 3cosx = 0.
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volfostapowkdlf
Соs2х=2сos^2(x)-1
cosx=t
2t^2-3t-1=0
D=9+8=17
t1=(3+√17)/4
t2=(3-√17)/4
t1>1=> x неіснуючий
t2:cosx=(3-√17)/4=>x=+-arccos((3-√17)/4)+2πk,kєZ
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Answers & Comments
cosx=t
2t^2-3t-1=0
D=9+8=17
t1=(3+√17)/4
t2=(3-√17)/4
t1>1=> x неіснуючий
t2:cosx=(3-√17)/4=>x=+-arccos((3-√17)/4)+2πk,kєZ