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ElbekXD
@ElbekXD
June 2022
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sangers1959
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(x²-x-2)/(x²-4)=0 ОДЗ: x²-4≠0 x²-2²≠0 (x+2)(x-2)≠0 x≠-2 x≠2
(x²-x-x+x-2)=0
(x-2x+x-2)=0
(x(x-2)+(x-2))=0
(x-2)(x+1)=0
x₁=-1 x₂=2 ∉ согласно ОДЗ
Ответ: x=-1. (Г)
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Answers & Comments
Verified answer
(x²-x-2)/(x²-4)=0 ОДЗ: x²-4≠0 x²-2²≠0 (x+2)(x-2)≠0 x≠-2 x≠2(x²-x-x+x-2)=0
(x-2x+x-2)=0
(x(x-2)+(x-2))=0
(x-2)(x+1)=0
x₁=-1 x₂=2 ∉ согласно ОДЗ
Ответ: x=-1. (Г)