h1=2 h2=3.8 v=?
m*g*h1+m*v²/2=m*g*h2
v=√(2*g*(h2-h1))=√(2*10*(3.8-2))=6 м/с
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h1=2 h2=3.8 v=?
m*g*h1+m*v²/2=m*g*h2
v=√(2*g*(h2-h1))=√(2*10*(3.8-2))=6 м/с
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Verified answer
0.5*m*V(y)^2+m*g*h(1)=mgh(2)0.5V(y)^2+10*2=10*3.8---->V(y)^2=36--->V(y)=6 m/s