x²-4x+2=0
D= 16-8= 8
x1= (4+2√2)/2= 2+√2
x2= (4-2√2)/2= 2-√2
x1*x2(x1+x2)= (2+√2)(2-√2)(2+√2+2-√2)= (4-2)*4= 8
Ответ (2)
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Verified answer
x²-4x+2=0
D= 16-8= 8
x1= (4+2√2)/2= 2+√2
x2= (4-2√2)/2= 2-√2
x1*x2(x1+x2)= (2+√2)(2-√2)(2+√2+2-√2)= (4-2)*4= 8
Ответ (2)