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OwnInfinity
@OwnInfinity
July 2022
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Доказать:
1) 1+2sinacosa/(sina+cosa)^2=1
2) sin^2a-cos^2a+1/sin^2a=2
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олятруш
1) по формулам двойного угла
(1+sin 2a)/(1+sin 2a)=1, 1=1, верно
2)sin²a-cos²a+1=1-cos2a=2sin²a
2sin²a/sin²a=2, 2=2, верно
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Answers & Comments
(1+sin 2a)/(1+sin 2a)=1, 1=1, верно
2)sin²a-cos²a+1=1-cos2a=2sin²a
2sin²a/sin²a=2, 2=2, верно