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July 2022
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Покажите тождество по тригонометрии
Sin2A-(sinA+cosA)^2/sin^2A+cos^2A. Ко всей дроби +1=0 А-альфа
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pomoshnik09
Используем формулы sin2α=2sinαcosα sin²α+cos²α=1
sin2α-(sin²α+2sinαcosα+cos²α)/1 +1=0
sin2α-(1+sin2α)+1=0
sin2α-1-sin2α-1+1=0 0=0 тождество верно
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Answers & Comments
sin2α-(sin²α+2sinαcosα+cos²α)/1 +1=0
sin2α-(1+sin2α)+1=0
sin2α-1-sin2α-1+1=0 0=0 тождество верно