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Sidorovich
@Sidorovich
July 2022
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cos3x/sin2x=1 при 170(градусов)<x<280(градусов)
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sedinalana
Cos3x=sin2x
cos3x-cos(π/2-2x)=0
-2sin(x/2+π/4)sin(5x/2-π/4)=0
sin(x/2+π/4)=0
x/2+π/4=πk
x/2=-π/4+πk
x=-π/2+2πk,k∈z
sin(5x/2-π/4(=0
5x/2-π/4=πk
5x/2=π/4+πk
x=π/10+2πk/5,k∈z
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Answers & Comments
cos3x-cos(π/2-2x)=0
-2sin(x/2+π/4)sin(5x/2-π/4)=0
sin(x/2+π/4)=0
x/2+π/4=πk
x/2=-π/4+πk
x=-π/2+2πk,k∈z
sin(5x/2-π/4(=0
5x/2-π/4=πk
5x/2=π/4+πk
x=π/10+2πk/5,k∈z