АЛГЕБРА, ПОМОГИТЕВЫЧИСЛИТЕ COS6X/COS2X - SIN6X/SIN2X. Created by anonim7917. algebra-ru

SIN2X...

anonim7917 @anonim7917

July 2022 1 8 Report

АЛГЕБРА, ПОМОГИТЕ
ВЫЧИСЛИТЕ COS6X/COS2X - SIN6X/SIN2X

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NNNLLL54

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Ответ:

$\dfrac{cos6x}{cos2x}-\dfrac{sin6x}{sin2x}=\dfrac{cos6x\cdot sin2x-sin6x\cdot cos2x}{sin2x\cdot cos2x}=\dfrac{sin(2x-6x)}{\frac{1}{2}\cdot sin4x}=\dfrac{2sin(-4x)}{sin4x}=\\\\\\=\dfrac{-2sin4x}{sin4x}=-2$

4 votes Thanks 3

Fill in the correct form of the Infinitive to make Complex Object. 1. Our teacher made us (do) this exercise all over again. (rewrite)

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anonim7917 June 2023 | 0 Ответы

1 x 4

Answer

anonim7917 June 2023 | 0 Ответы

1521x1gt22

Answer

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Verified answer

5e3e45b6ae85ff50c34645758aa4ba08

20 15 64a2d712962ca

2710 27

50 64a2247bd63c9

30 64a0e01e1ce74

144 8 649ca4954f2f1

502cda01cdfefd99e74683471b3949bf

Fill in the correct form of the Infinitive to make Complex Object. 1. Our teacher made us (do) this exercise all over again. (rewrite)

1 x 4

1521x1gt22

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