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moncumonc
@moncumonc
July 2022
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(1/sinα - 1/sin3α)(sinα+sin5α)-2
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oganesbagoyan
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(1/sinα - 1/sin3α)(sinα+sin5α)-2==(sin3α - sinα)(sinα+sin5α)/(sinα*sin3α)-2=2sinα*cos2α*2sin3α*cos2α/(sinα*sin3α)-2 =
=4cos²2α-2=2(2cos²2α-1)=2cos4αα
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moncumonc
сюда вместо альфа еще нужно подставить 15 градусов
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(1/sinα - 1/sin3α)(sinα+sin5α)-2==(sin3α - sinα)(sinα+sin5α)/(sinα*sin3α)-2=2sinα*cos2α*2sin3α*cos2α/(sinα*sin3α)-2 ==4cos²2α-2=2(2cos²2α-1)=2cos4αα