Вычислить: 24 / (sin(49)^2 + cos(131)^2). Created by arbuzni4nik. algebra-ru

(sin(49)^2 + cos(131)^2)...

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Вычислить: 24 / (sin(49)^2 + cos(131)^2)

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$\dfrac{24}{Sin^{2}49^\circ+Cos^{2}131^\circ}=\dfrac{24}{Sin^{2}49^\circ+Cos^{2}(180^\circ-49^\circ) } =\dfrac{24}{\underbrace{Sin^{2}49^\circ+Cos^{2}49^\circ}_{1} }=\\\\=\frac{24}{1} =\boxed{24}$

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Answers & Comments

Verified answer

cos 2x 3 sin 2x

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cos2x3pi cos2x 1

her students to make p__. 2.i have to get a good g__ for this exam if i want to ...

x = 2...

zavisit li pokazatel prelomleniya ot ugla padeniya otvet obosnujte

najdite znachenie vyrazheniya a2 36 a 6 1 a

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