дано
Vppa(H2SO4) = 1 L = 1000 ml
W(H2SO4) = 96%
p(H2SO4) =1.84 g/cm3
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m(ppa 1% H2SO4)-?
m(H2SO4) = V(H2SO4) * W(H2SO4) * p(H2SO4) / 100%
m(H2SO4) = 1000 * 96%* 1.84 /100% = 1766.4 g
m( 1% ppa H2SO4) = 1766.4 * 100% / 1% = 176640 g
ответ 176640 г
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Verified answer
дано
Vppa(H2SO4) = 1 L = 1000 ml
W(H2SO4) = 96%
p(H2SO4) =1.84 g/cm3
----------------------------------
m(ppa 1% H2SO4)-?
m(H2SO4) = V(H2SO4) * W(H2SO4) * p(H2SO4) / 100%
m(H2SO4) = 1000 * 96%* 1.84 /100% = 1766.4 g
m( 1% ppa H2SO4) = 1766.4 * 100% / 1% = 176640 g
ответ 176640 г