August 2021 0 29 Report
СН4+2О2=СО2+2Н2О+802кДж вычислите количество теплоты выдел.при сжигании 24 г метана.

при взаимодействии 213 грамм хлора с натрием выдел. 1233,9 кДж теплоты, составьте ТХУ 
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