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enotik39
@enotik39
October 2021
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Снова помогите с решением логарифмов, пожалуйста
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kirichekov
Verified answer
Log₁/₂ 18+log₂72+5^log₅2=-log₂18+log₂72+2=log₂(72/18)+2=log₂4+2=2+2=4
преобразовать показатель:
log₁/₁₂₅ (1/8)=log₅⁻³ (1/8)=(-1/3)*log₅(1/8)=log₅ (1/8)^(-1/3)=log₅2
5^(log₅2)=2
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kirichekov
"ПОМОГИТЕ логарифмами". такое задание?
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Answers & Comments
Verified answer
Log₁/₂ 18+log₂72+5^log₅2=-log₂18+log₂72+2=log₂(72/18)+2=log₂4+2=2+2=4преобразовать показатель:
log₁/₁₂₅ (1/8)=log₅⁻³ (1/8)=(-1/3)*log₅(1/8)=log₅ (1/8)^(-1/3)=log₅2
5^(log₅2)=2