Сократите алгебраические дроби:
1) 12a^2b+8ab^2
____________
9a^2-4b^2
2) 36c^2-60c+25
25-36c^2
=(4ab( 3a + 2b))\ (3a-2b)(3a+2b)= 4ab \ 3a - 2b
= ((6c-5)^2)\ (5-6c)(5+6c) = (6c-5)^2 \ -(6c-5)(6c+5) = 6c-5 \ 6c+5
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Answers & Comments
=(4ab( 3a + 2b))\ (3a-2b)(3a+2b)= 4ab \ 3a - 2b
= ((6c-5)^2)\ (5-6c)(5+6c) = (6c-5)^2 \ -(6c-5)(6c+5) = 6c-5 \ 6c+5