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bbbelka
@bbbelka
July 2022
1
1
Report
Сократите дробь 80(в степени n)
2(в степени 4n+2)*5(в степени n-1)
Должно получиться 1,25
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1996sasha
80( n)
=
16( n) * 5 ( n)
=
2(4n)*5(n)
2(4n+2)*5(n-1) 2(4n+2)*5(n-1) 2(4n+2)*5(n-1)
=
2(
4n-
4n-2)* 5(
n-
n+1)=2 (-2) *5 (1)= 1\4*5=5|4=1,25
6 votes
Thanks 10
bbbelka
Спасибо всем! Вы мен очень помогли!!!!
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Answers & Comments
2(4n+2)*5(n-1) 2(4n+2)*5(n-1) 2(4n+2)*5(n-1)
=
2(4n-4n-2)* 5(n-n+1)=2 (-2) *5 (1)= 1\4*5=5|4=1,25