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Теллур
@Теллур
July 2022
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Спасите
6sin^2x-sinx=1
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ciklo
6sin^2x-sinx-1=0
sinx=t
6t^2-t-1=0
D=25
t1=-1/3
t2=1/2
_____________
sinx=-1/3
x=(-1)^k arcsin(-1/3)+пk
x=(-1)^k+1 arcsin(1/3)+пk
sinx=1/2
x=(-1)^k arcsin(п/6)+пk
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Answers & Comments
sinx=t
6t^2-t-1=0
D=25
t1=-1/3
t2=1/2
_____________
sinx=-1/3
x=(-1)^k arcsin(-1/3)+пk
x=(-1)^k+1 arcsin(1/3)+пk
sinx=1/2
x=(-1)^k arcsin(п/6)+пk