Ответ:

FeCL3+3NaOH-->Fe(OH)3+3NaCL

2Fe(OH)3-->Fe2O3+3H2O

Fe2O3+6HNO3-->2Fe(NO3)3+3H2O

Fe2O3+3H2-->2Fe+3H2O

Fe+2HCL-->FeCL2+H2

FeCL2+2NaOH-->Fe(OH)2+2NaCL

дано

m(HCL) = 365

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n(NaCL) - ?

HCL+NaOH-->NaCL+H2O

M(HCL) = 36.5 g/mol

n(HCL) = m(HCL) / M(HCL) = 365 / 36.5 = 10 mol

n(HCL) = n(NaCL) = 10 mol

n(NaCL) = 10 mol

M(NaCL) = 58.5 g/mol

m(NaCL) = n(NaCL) * M(NaCL) = 10 * 58.5 = 585 g

ответ 10 моль , 585 г

Объяснение: