Ответ:
1)arcCos(-1)+2arcCos 1 2 = pi+ pi 3 2)arcCoslπ 1 - pi = 0 - pi = - pi 3)arcSin(- 1 2 )-arcCos sqrt 3 2 =- pi 6 - pi 6 = 4)arcSin 1 2 +arcCos(- sqrt 3 2 )= pi 6 + 5 pi 6 = 5)arcSin1+arcCos(-1)= pi 2 + pi= 6)arcCos(- sqrt 2 2 )-arcCos sqrt 2 2 = 3 pi 4 - pi 4
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
1)arcCos(-1)+2arcCos 1 2 = pi+ pi 3 2)arcCoslπ 1 - pi = 0 - pi = - pi 3)arcSin(- 1 2 )-arcCos sqrt 3 2 =- pi 6 - pi 6 = 4)arcSin 1 2 +arcCos(- sqrt 3 2 )= pi 6 + 5 pi 6 = 5)arcSin1+arcCos(-1)= pi 2 + pi= 6)arcCos(- sqrt 2 2 )-arcCos sqrt 2 2 = 3 pi 4 - pi 4