Ответ:
Пошаговое объяснение:
(sinα+cosα)²/(1+sin2α)=(sin²α+2sinα*cosα+cos²α)/(1+2*sinα*cosα)=
=(sin²α+cos²α+2*sinα*cosα)/(1+2*sinα*cosα)=(1+2*sinα*cosα)/(1+2*sinα*cosα)=1
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Ответ:
Пошаговое объяснение:
(sinα+cosα)²/(1+sin2α)=(sin²α+2sinα*cosα+cos²α)/(1+2*sinα*cosα)=
=(sin²α+cos²α+2*sinα*cosα)/(1+2*sinα*cosα)=(1+2*sinα*cosα)/(1+2*sinα*cosα)=1