Mr(Ba(OH)2)=137*2*16+2*1=171
W(O)=32/171=0,19 - 19%
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Mr(Ba(OH)2)=137*2*16+2*1=171
W(O)=32/171=0,19 - 19%
W(O)=Ar(O)*n/ Mr(Ba(OH)2 *100%=16*2/171 *100%=19%