СРОЧНО!!! ПОМОГИТЕ ПЛИИИЗЗЗ. Created by miliaushaahyar. algebra-ru

1∛(12*6²*0,5)=∛(6*36)=62a)3^x*(9+1)=8103^x=81x=4б)7^x-7^(x-1)=67^(x-1)*(7-1)=67^(x-1)=1x-1=0x=1в)3^5*(3^-4)^(3x-2)=(3³)^(x+3)3^(5-12x+8)=3^(3x+9)13-12x=3x+93x+12x=13-915x=4x=4/153(2²)^(2x+3)<2^-210x+15<-210x<-17x<-1,7x∈(-∞;-1,7)4{2^(2x+2y)=2^7⇒2x+2y=7{5^(3x-2y-3)=1⇒3x-2y-3=0⇒3x-2y=3прибавим5x=10x=24+2y=72y=3y=1,5Ответ (2;1,5)Новые вопросы в АлгебраПомогите пожалуйста1.Упростите выражение1-sin^2a/cos^2a2.(1-cosa)(1+сosa) С решением1)4sin²x-cosx-1=02)tgx=ctgx3) 3+sin2x=4sin²xустановите соответствие для арифметической прогрессии:1)а1=8 d=0,22)a1= -8d=0,23)a1=5d=0,3↓↓а)ограничена б) убывающаяс)а101=12д)а41≠0е)S41≠0Найдите пятый член арифметической прогрессии, если сумма его n членов задана формулой Sn=n²-3nНайдите сумму первых 13-ти членов арифметической прогрессии, если известно что а5+а9=12Найдите сумму первых 6-ти членов арифметической прогрессии (аn) если а21=33, а39=36,6.в арифметической прогрессии (an) а13=17найдите а8+а18прошу пожалуйста помогите, почему никто не отвечает: а5=7 а11=10, найдите а21даю 10 баллов прошу помочьПрошу срочно помогите!!ПредыдущийСледующийВместе мы знаем большеЭтот сайт использует cookies Политика Cookies . 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СРОЧНО!!! ПОМОГИТЕ ПЛИИИЗЗЗ...

miliaushaahyar @miliaushaahyar

May 2022 1 31 Report

СРОЧНО!!! ПОМОГИТЕ ПЛИИИЗЗЗ

Answers & Comments

sedinalana 1
∛(12*6²*0,5)=∛(6*36)=6
2
a)3^x*(9+1)=810
3^x=81
x=4
б)7^x-7^(x-1)=6
7^(x-1)*(7-1)=6
7^(x-1)=1
x-1=0
x=1
в)3^5*(3^-4)^(3x-2)=(3³)^(x+3)
3^(5-12x+8)=3^(3x+9)
13-12x=3x+9
3x+12x=13-9
15x=4
x=4/15
3
(2²)^(2x+3)<2^-2
10x+15<-2
10x<-17
x<-1,7
x∈(-∞;-1,7)
4
{2^(2x+2y)=2^7⇒2x+2y=7
{5^(3x-2y-3)=1⇒3x-2y-3=0⇒3x-2y=3
прибавим
5x=10
x=2
4+2y=7
2y=3
y=1,5
Ответ (2;1,5)