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miliaushaahyar
@miliaushaahyar
July 2022
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СРОЧНО!!! ПОМОГИТЕ ПЛЗЗЗЗЗ!!!
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sedinalana
1
∛(6*18*2)=∛216=6
2
(3²)^x=(3^-3)^(2-x)
3^(2x)=3^(-6+3x)
2x=-6+3x
3x-2x=6
x=6
б)5^(x-1)*(10+25)=7
5^(x-1)=1/5
x-1=-1
x=0
в)3^x*(4*9+5*3-6)=5
3^x=(36+15-6)=5
3^x*45=5
3^x=1/9
x=-2
3
(3³)^(2-x)>(3²)(2x-1)
6-3x>4x-2
-3x-4x>-2-6
-7x>-8
x<8/7
x∈(-∞;8/7)
4
6^(x+y)=216
x+y=3
y=3-x
3^x+3^(3-x)=12
3^x+27/3^x -12=0
3^x=t
t+27/t-12=0
t²²-12t+27=0
t1+t2=12 U t1*t2=27
t1=3⇒3^x=3⇒x=1⇒y=3-1=2
t2=9⇒3^x=9⇒x=2⇒y=3-2=1
Ответ (1;2);(2;1)
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Answers & Comments
∛(6*18*2)=∛216=6
2
(3²)^x=(3^-3)^(2-x)
3^(2x)=3^(-6+3x)
2x=-6+3x
3x-2x=6
x=6
б)5^(x-1)*(10+25)=7
5^(x-1)=1/5
x-1=-1
x=0
в)3^x*(4*9+5*3-6)=5
3^x=(36+15-6)=5
3^x*45=5
3^x=1/9
x=-2
3
(3³)^(2-x)>(3²)(2x-1)
6-3x>4x-2
-3x-4x>-2-6
-7x>-8
x<8/7
x∈(-∞;8/7)
4
6^(x+y)=216
x+y=3
y=3-x
3^x+3^(3-x)=12
3^x+27/3^x -12=0
3^x=t
t+27/t-12=0
t²²-12t+27=0
t1+t2=12 U t1*t2=27
t1=3⇒3^x=3⇒x=1⇒y=3-1=2
t2=9⇒3^x=9⇒x=2⇒y=3-2=1
Ответ (1;2);(2;1)