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@gfdghhdghfdf
July 2022
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СРОЧНО!!!!!!!!!! ПОМОГИТЕ РЕШИТЬ!!!!!!!!!!!!!!
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Checov7400
Решение в приложении.
2 votes
Thanks 1
Lyugod
(b-1)²·(1/(b-1)²+1/(b²-1)+2/(b+1))=(b-1)²·(1/(b-1)(b-1)+1/(b-1)(b+1))+2/(b+1)=
=(b-1)²·(1·(b+1)+1·(b-1))/(b-1))(b-1)(b+1)+2/(b+1)=
(b-1)²·(b+1+b-1)/(b-1)²(b+1)+2/(b+1)=
2b/(b+1)+2/(b+1)=(2b+2)/(b+1)=2(b+1)/(b+1)=2.
1 votes
Thanks 1
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Answers & Comments
=(b-1)²·(1·(b+1)+1·(b-1))/(b-1))(b-1)(b+1)+2/(b+1)=
(b-1)²·(b+1+b-1)/(b-1)²(b+1)+2/(b+1)=
2b/(b+1)+2/(b+1)=(2b+2)/(b+1)=2(b+1)/(b+1)=2.