Ответ:0.28л
Дано: Решение :
m(Ag)=2.7г C2H2+H2O=CH3COH
Найти: CH3COH+Ag2O=CH3COOH+2Ag↓
V(C2H2)=? n(Ag)=m(Ag)M(Ag)=2.7108=0.025 моль
n(C2H2)=n(CH3COH)=n(Ag)2=0.0252=0.0125 моль
V(C2H2)=n(C2H2)⋅V(C2H2)=0.0125⋅22.4=0.28лV(C2H2)=n(C2H2)⋅V(C2H2)=0.0125⋅22.4=0.28л
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Ответ:0.28л
Дано: Решение :
m(Ag)=2.7г C2H2+H2O=CH3COH
Найти: CH3COH+Ag2O=CH3COOH+2Ag↓
V(C2H2)=? n(Ag)=m(Ag)M(Ag)=2.7108=0.025 моль
n(C2H2)=n(CH3COH)=n(Ag)2=0.0252=0.0125 моль
V(C2H2)=n(C2H2)⋅V(C2H2)=0.0125⋅22.4=0.28лV(C2H2)=n(C2H2)⋅V(C2H2)=0.0125⋅22.4=0.28л