СРОЧНО ПРОШУ 2×(х+11)>3×(6-х) (х-3)×(х+6)>(х+5)×(х-4). Created by teh777765. algebra-ru

СРОЧНО ПРОШУ 2×(х+11)>3×(6-х) (х-3)×(х+6)>(х+5)×(х-4)...

teh777765 @teh777765

August 2022 1 1 Report

СРОЧНО ПРОШУ
2×(х+11)>3×(6-х)
(х-3)×(х+6)>(х+5)×(х-4)

Answers & Comments

abdullayevallayar141

Ответ:

В решении

Объяснение:

$2(x + 11) > 3(6 - x) \\ 2x + 22 > 18 - 3x \\ 2x + 3x > 18 - 22 \\ 5x > - 4 \\ x > \ - \frac{4}{5} \\ x∈( - \frac{4}{5} ; \infty ) \\ \\ (x - 3)(x + 6) > (x + 5)(x - 4) \\ x {}^{2} + 6x - 3x - 18 > x {}^{2} - 4x + 5x - 20 \\ x {}^{2} - x {}^{2} + 3x - x - 18 + 20 > 0 \\ 2x + 2 > 0 \\ 2(x + 1) > 0 \\ x + 1 > 0 \\ x > - 1 \\ x∈( - 1; \infty )$

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