СРОЧНО РЕШИТЬ НЕРАВЕНСТВО. Created by northde. algebra-ru

СРОЧНО РЕШИТЬ НЕРАВЕНСТВО...

Miroslava227

Ответ:

$\displaystyle 2sin\Big(\frac{\pi }{4}-x\Big)\leq \sqrt2\\\\\\sin\Big(\frac{\pi }{4}-x\Big)\leq \frac{\sqrt2}{2}\\\\\\-\frac{5\pi }{4}+2\pi n\leq \Big(\frac{\pi }{4}-x\Big)\leq \frac{\pi }{4}+2\pi n\ ,\ n\in Z\\\\\\-\frac{3\pi }{2}+2\pi n\leq -x\leq 2\pi n\ ,\ n\in Z\\\\\\2\pi n\leq x\leq \frac{3\pi }{2}+2\pi n\ ,\ n\in Z\\\\\\x\in \Big[\ 2\pi n\ ;\ \frac{3\pi }{2}+2\pi n\ \Big]\ ,\ n\in Z$

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NNNLLL54

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Ответ:

решение на фотографии.

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