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andderzhawinsky2015
@andderzhawinsky2015
July 2022
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СРОЧНО!!! Решить задачу по геометрии профильной:
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армения20171
Verified answer
<ACH=180°-120°=60°
<HAC=30°
CH=AC/2=7√3
∆AHC;<AHC=90°
BC²=AH²+CH²
(14√3)²=AH²+(7√3)²
AH²=196*3-49*3=4*49*3-49*3=
49*3(4-1)=49*9
AH=7*3=21
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Answers & Comments
Verified answer
<ACH=180°-120°=60°<HAC=30°
CH=AC/2=7√3
∆AHC;<AHC=90°
BC²=AH²+CH²
(14√3)²=AH²+(7√3)²
AH²=196*3-49*3=4*49*3-49*3=
49*3(4-1)=49*9
AH=7*3=21