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yan0176
@yan0176
July 2022
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СРОЧНО!!!!! С ДАНО!
Вычислите объем воздуха, необходимый для полного сгорания 67,2 л метиламина.
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ladusss
Дано:
V(CH3NH2)=67,2 л.
Найти:
V(возд.)—?
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Answers & Comments
V(CH3NH2)=67,2 л.
Найти:
V(возд.)—?