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elenakoroleva2011
@elenakoroleva2011
August 2021
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СРОЧНО! Вычислите sin 22°30'. Можно по подробнее, с формулами
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sedinalana
Verified answer
Sin²a=(1-cos2a)/2
sin²22,5=(1-cos45)/2=(1-√2/2)/2=(2-√2)/4
sin22,5=√(2-√2)/2
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Answers & Comments
Verified answer
Sin²a=(1-cos2a)/2sin²22,5=(1-cos45)/2=(1-√2/2)/2=(2-√2)/4
sin22,5=√(2-√2)/2