AB= 3
по теореме косинусов:
АВ²=(4√2)²+√5²-2×4√2×5×cos45
cos45=√2/2
AB²=49-40√2×√2/2
АВ²=9
АВ=3
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AB= 3
по теореме косинусов:
АВ²=(4√2)²+√5²-2×4√2×5×cos45
cos45=√2/2
AB²=49-40√2×√2/2
АВ²=9
АВ=3