Ответ:
Объяснение:
1) Mr(Rb3PO4) =85*3 + 31 + 16*4 =350
W(Rb) = Ar(Rb) *n / Mr(Rb3PO4) *100% = 85*3 / 350 *100% =50%
2) Mr(Sr(NO3)2) = 88 + 14*2 + 16*6 =212
W(Sr) = Ar(Sr) *n / Mr(Sr(NO3)2) *100% = 88 *1 / 212 *100% =41,5%
3) Mr(In(OH)3) = 115 + 16*3 + 1*3 =166
W(In) = Ar(In) *n / Mr(In(OH)3) *100% = 115 *1 / 166 *100% =69%
4) Mr(Al2(SiO3)3) = 27*2 + 28 *3 + 16*9 = 282
W(Si) = Ar(Si) *n / Mr(Al2(SiO3)3) *100% = 28*3 / 282 *100% =30%
5) Mr(Sb2O5) = 122 *2 + 16*5 =324
W(Sb) = Ar(Sb) *n / Mr(Sb2O5) *100% = 122 *2 / 324 *100% =75%
6) Mr(H2Se) = 1*2 + 79 = 81
W(Se) = Ar(Se) *n / Mr(H2Se) *100% = 79 * 1 / 81 *100% =97,5 %
7) Mr(Br2O7) = 80 *2 + 16*7 =272
W(Br) = Ar(Br) *n / Mr(Br2O7) *100% = 80*2 / 272 *100% =59%
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Ответ:
Объяснение:
1) Mr(Rb3PO4) =85*3 + 31 + 16*4 =350
W(Rb) = Ar(Rb) *n / Mr(Rb3PO4) *100% = 85*3 / 350 *100% =50%
2) Mr(Sr(NO3)2) = 88 + 14*2 + 16*6 =212
W(Sr) = Ar(Sr) *n / Mr(Sr(NO3)2) *100% = 88 *1 / 212 *100% =41,5%
3) Mr(In(OH)3) = 115 + 16*3 + 1*3 =166
W(In) = Ar(In) *n / Mr(In(OH)3) *100% = 115 *1 / 166 *100% =69%
4) Mr(Al2(SiO3)3) = 27*2 + 28 *3 + 16*9 = 282
W(Si) = Ar(Si) *n / Mr(Al2(SiO3)3) *100% = 28*3 / 282 *100% =30%
5) Mr(Sb2O5) = 122 *2 + 16*5 =324
W(Sb) = Ar(Sb) *n / Mr(Sb2O5) *100% = 122 *2 / 324 *100% =75%
6) Mr(H2Se) = 1*2 + 79 = 81
W(Se) = Ar(Se) *n / Mr(H2Se) *100% = 79 * 1 / 81 *100% =97,5 %
7) Mr(Br2O7) = 80 *2 + 16*7 =272
W(Br) = Ar(Br) *n / Mr(Br2O7) *100% = 80*2 / 272 *100% =59%