срочно...помогите плиз...Заранее спасибо4 и 5.... Created by SanchesBut. algebra-ru

срочно...помогите плиз...Заранее спасибо4 и 5...

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$4)\frac{a^{2}-4} {a+2} =\frac{(a+2)(a-2)}{a+2}=a-2\\\\2\frac{1}{37}-2= \frac{1}{37}\\\\5)(\frac{1}{x+5}+ \frac{10}{x^{2}-25})(x-5)=( \frac{1}{x+5} + \frac{10}{(x+5)(x-5)})(x-5)= \frac{x-5+10}{(x+5)(x-5)}*(x-5)= \frac{(x+5)(x-5)}{(x+5)(x-5)}=1$

ОДЗ :

1) x - 5 ≠ 0

x ≠ 5

2)x² - 25 ≠ 0

(x + 5)(x - 5) ≠ 0

x ≠ - 5 , x ≠ 5

2 votes Thanks 5

SanchesBut спасибо

elena20092

4. (а² - 4)/(а + 2) = а - 2 при а = 2 1/37 получаем

а - 2 = 2 1/37 - 2 = 1/37

5. ((1/(х + 5) + 10/(х² - 25)) · (х- 5) = ?

---------- ОДЗ: х ≠ -5 и х ≠ 5 -----------

= ((х - 5 + 10)/((х + 5)(х - 5))) · (х - 5) =

= ((х + 5)/((х + 5)(х - 5))) · (х - 5) =

= (1/(х - 5)) · (х - 5) = 1

0 votes Thanks 1

SanchesBut спасибо

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