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seminartem98
@seminartem98
July 2022
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√(t^2−16t+64)+t при t⩽8. Как решать данные задания
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Beladrino
A=√(t² -16t +64) +t =√(t -8)² +t =|t-8| +t,если t <8 то |t-8| = -(t-8) тогда A=-(t-8) +t =-t+8+t
=8
. (наверно это).
если t ≥8 то |t-8| =(t-8) тогда A=(t-8) +t =2t -8.
2 votes
Thanks 2
oganesbagoyan
Verified answer
Запиши то, то под корнем как (t-8)^2
тогда:
(t-8)+t=2t-8=2*8-8=16-8=8
3 votes
Thanks 3
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Answers & Comments
если t ≥8 то |t-8| =(t-8) тогда A=(t-8) +t =2t -8.
Verified answer
Запиши то, то под корнем как (t-8)^2тогда:
(t-8)+t=2t-8=2*8-8=16-8=8