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seriojka2002
@seriojka2002
October 2021
1
12
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X^2+7x/x-3 <0
(Там где "/" там дробь, и эта дробь меньше нуля)
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ВикаВикторовна
Verified answer
(х²+7х)/(х-3) < 0
ОДЗ: х-3≠0; х ≠ 3
х²+7х = 0
х(х+7)=0
х=0
х+7=0; х= -7
- + - +
-----------₀------------₀------------₀------>x
-7 0 3
x∈(-∞; -7)∪(0; 3)
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Answers & Comments
Verified answer
(х²+7х)/(х-3) < 0ОДЗ: х-3≠0; х ≠ 3
х²+7х = 0
х(х+7)=0
х=0
х+7=0; х= -7
- + - +
-----------₀------------₀------------₀------>x
-7 0 3
x∈(-∞; -7)∪(0; 3)