Решите уравнение:а) [tex] \frac{5x+2}{5x} [/tex] = 0б)[tex] \frac{(2x-1)(x+3)}{2x+1} [/tex] = 0. Created by CreepyChan. algebra-ru

tex] = 0...

July 2022 2 11 Report

Решите уравнение:
а) [tex] \frac{5x+2}{5x} [/tex] = 0
б)[tex] \frac{(2x-1)(x+3)}{2x+1} [/tex] = 0

mexan3122 $\frac{5x+2}{5x} = 0
\\\\
5x \neq 0
\\\
5x+2=0
\\\\
x \neq 0
\\\
x=-0.4
$

$\frac{(2x-1)(x+3)}{2x+1} = 0
\\\
2x-1=0
\\\
x+3=0
\\\
2x+1= \neq 0
\\\\
x=0.5
\\\
x=-3
\\\
x \neq -0.5$

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Artem112

Verified answer

1. 5х неравно 0
5х+2 = 0
5х = 2
х = 0,4
2. 2х+1 неравно 0, значит х неравно -0,5
Числитель равен нулю
2х - 1 = 0 либо х + 3 = 0
х = 0,5 либо х = -3

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