Решите уравнение:
а) [tex] \frac{3x-4}{4} [/tex] = 0
б) [tex] \frac{x(x+1)}{x^{2}+1 } [/tex] = 0
а) [tex] \frac{3x-4}{4} [/tex] = 0
б) [tex] \frac{x(x+1)}{x^{2}+1 } [/tex] = 0
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Verified answer
A) 3x-4/4 = 0 | * 43x - 4 = 0
3x = 4
x = 1 1/3
б)x(x+1)/x^2 + 1 = 0 | *(x^2+1)
x= 0
или
x=-1