Verified answer

Ответ: x=2 ; y=5

{x/8+3y/4=4

{x/2-2y/5=-1

{(x+6y)/8=4

{(5x-4y)/10=-1

{x+6y=32 |•(-5)

{5x-4y=-10

{-5x-30y=-160

{5x-4y=-10

Прибавляем системы

-34y=-170

y=5

Вместо у поставим 5

x+6y=32

x+6•5=32

x+30=32

x=2

[tex]\displaystyle \left \{ {{\frac{x}{8}+\frac{3y}{4}=4 } \atop {\frac{x}{2}-\frac{2y}{5}=-1 }} \right.\\ \\\left \{ {{\frac{x}{8}+\frac{3y}{4}=4 } \atop {x=-2+\frac{4}{5}y }} \right. \\\\\frac{-2+\frac{4}{5}y }{8}+\frac{3y}{4}=4\\ \\y=5\\ \\x=-2+\frac{4}{5}*5\\ \\x=2\\(x,y)=(2,5)[/tex]