Решить уравнения:
Решение:
1)
x = 0
2)
1 + sin 2x = 2 sin x + cos x
1 + 2 sin x · cos x -2 sin x - cos x = 0
(1 - cos x) - 2 sin x · (1 - cos x) = 0
(1 - cos x) · (1 - 2 sin x) = 0
a)
1 - cos x = 0
cos x = 1
x₁ = 2πk (k ∈ Z)
б)
1 - 2 sin x = 0
2 sin x = 1
sin x = 0.5
x₂ = π/6 + 2πm (m ∈Z)
x₃ = 5π/6 + 2πn (n ∈Z)
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Answers & Comments
Решить уравнения:
Решение:
1)
x = 0
2)
1 + sin 2x = 2 sin x + cos x
1 + 2 sin x · cos x -2 sin x - cos x = 0
(1 - cos x) - 2 sin x · (1 - cos x) = 0
(1 - cos x) · (1 - 2 sin x) = 0
a)
1 - cos x = 0
cos x = 1
x₁ = 2πk (k ∈ Z)
б)
1 - 2 sin x = 0
2 sin x = 1
sin x = 0.5
x₂ = π/6 + 2πm (m ∈Z)
x₃ = 5π/6 + 2πn (n ∈Z)