[tex]\displaystyle\bf\\\\\pi \approx3,14\\\\\pi +1\approx 4,14\\\\4,14\approx \sqrt{17,1396} \\\\\sqrt{17,1396} > \sqrt{17} \\\\\\\boxed{\pi +1 > \sqrt{17} }[/tex]
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[tex]\displaystyle\bf\\\\\pi \approx3,14\\\\\pi +1\approx 4,14\\\\4,14\approx \sqrt{17,1396} \\\\\sqrt{17,1396} > \sqrt{17} \\\\\\\boxed{\pi +1 > \sqrt{17} }[/tex]