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[tex] \frac{1}{3} ( log_{ \frac{1}{3} }\frac{1}{27} + log_{ \frac{1}{2} }64) [/tex]
[tex] \frac{1}{3} ( log_{ \frac{1}{3} }\frac{1}{27} + log_{ \frac{1}{2} }64) [/tex]
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[tex]\displaystyle \frac{1}{3}*(log_{3^{-1}}3^{-3}+log_{2^{-1}}2^6)=\frac{1}{3}(3log_33-6log_22)=\\\\=\frac{1}{3}(3-6)=\frac{1}{3}*(-3)=-1[/tex]