Ответ:
Объяснение:
[tex]\frac{2x-14}{x^2-10x+21}=\frac{2(x-7)}{(x-7)(x-3)}=\frac{2}{(x-3)};\\x=2,8; \frac{2}{x-3}=\frac{2}{2,8-3}=\frac{2}{-0,2}=-10[/tex]
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Ответ:
Объяснение:
[tex]\frac{2x-14}{x^2-10x+21}=\frac{2(x-7)}{(x-7)(x-3)}=\frac{2}{(x-3)};\\x=2,8; \frac{2}{x-3}=\frac{2}{2,8-3}=\frac{2}{-0,2}=-10[/tex]