Ответ:
a) 2sin 75°cos 75°=sin 150°=1/2
б) cos 15°²=1+cos30°/2=2+√3/4
в) 1-sin(π/12)²=соs(π/12)²=1+cos(π/6)/2=2+√3/4
г) 2tan 165°/1-tan (165°)²=tan 330°=-√3/3
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Ответ:
a) 2sin 75°cos 75°=sin 150°=1/2
б) cos 15°²=1+cos30°/2=2+√3/4
в) 1-sin(π/12)²=соs(π/12)²=1+cos(π/6)/2=2+√3/4
г) 2tan 165°/1-tan (165°)²=tan 330°=-√3/3