Verified answer

Ответ: x1=8   ; x=√1/128

Пошаговое объяснение:

Прологарифмируем по 2

(5-2*log(2;x))*log(2;8x) =log(2;1/64)

(5-2*log(2;x))*(log(2;8)+log(2;x)) = -6

(5-2*log(2;x))*(3+log(2;x)) = -6

15+5log(2;x)-6log(2;x) -2(log(2;x))²=-6

-log(2;x) -2(log(2;x))² = - 21

Сделаем замену у= log(2;x)

=> 2y²+y-21=0

y1=3    y2=-(7/2)

=> log(2;x)=3 => x1=8   log(2;x)=-7/2 => x=√1/128