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natchiy03
@natchiy03
May 2022
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дана геометрическая прогрессия (bⁿ) знаменатель которой равен [tex] \frac{1}{2} [/tex] а b₁=80. найдите b₇
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musamusaev
Bn=b*q^n-1
b7=80*1/2^6=5\2
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b7=80*1/2^6=5\2