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msblvck
@msblvck
August 2022
2
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найдите производную функции f(x)=x[tex] \sqrt{3x} [/tex]
найдите производную функции f(x)=x^4sin2x
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zahargm808
√(3x)=
√3/(2√x)
f(x)=x^4sin2x
4x^3*sin(2x)+2x^4*cos(2x)
2 votes
Thanks 2
чижiк
( √3х) `= ((3х) ^ 1/2) '= 1/2 × (3x) ^ - 1/2 × (3x)` = 1 / (2√3x) × 3 = 3 / (2√ 3x)
(х ^ 4 × sin2x) `= 4x ^ 3 ×sin2x+2x^4×cos2x
1 votes
Thanks 2
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Answers & Comments
f(x)=x^4sin2x
4x^3*sin(2x)+2x^4*cos(2x)
(х ^ 4 × sin2x) `= 4x ^ 3 ×sin2x+2x^4×cos2x