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shchipakinas
@shchipakinas
July 2022
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[tex] f (x) = \sqrt{ 6x +1 } [/tex]
найдите значение производной
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MizoriesKun
Verified answer
F(x)⁾=√(6x+1)⁾=((6x+1)¹/²)⁾ = (1/2) *(6x+1)⁻¹/²) *(6x+1)⁾= 6 /(2*√(6x+1)) =
=3/√(6x+1)
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Answers & Comments
Verified answer
F(x)⁾=√(6x+1)⁾=((6x+1)¹/²)⁾ = (1/2) *(6x+1)⁻¹/²) *(6x+1)⁾= 6 /(2*√(6x+1)) ==3/√(6x+1)