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alexandraa
@alexandraa
July 2022
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ПОМОГИТЕ РЕШИТЬ УРАВНЕНИЕ
2sinx=[tex] \sqrt{3} [/tex] на отрезке [ [tex] \frac{ \pi }{2}; \pi[/tex] ]
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Lesben
2sinx=√3 , x∈/π/2,π/
sinx=√3/2
sin60°=sin120°
120°∈/π/2,π/
Otvet: x=120°
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Answers & Comments
sinx=√3/2
sin60°=sin120°
120°∈/π/2,π/
Otvet: x=120°