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@0007инкогнет0007
July 2022
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Найти неопределенный интеграл:[tex] \int\limits^ {} \,\frac{ln^{4}(3x+1)}{3x+1} dx [/tex]
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artalex74
Заметим, что
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Answers & Comments
Заметим, что
Поэтому![\int\limits {\frac{\ln^4(3x+1) }{3x+1} dx = \frac{1}{3}\int \ln^4(3x+1) d\ln (3x+1) =\left[\begin{array}{c} \ln(3x+1)=t \end{array}\right] = \int\limits {\frac{\ln^4(3x+1) }{3x+1} dx = \frac{1}{3}\int \ln^4(3x+1) d\ln (3x+1) =\left[\begin{array}{c} \ln(3x+1)=t \end{array}\right] =](https://tex.z-dn.net/?f=%20%5Cint%5Climits%20%7B%5Cfrac%7B%5Cln%5E4%283x%2B1%29%20%7D%7B3x%2B1%7D%20dx%20%3D%20%5Cfrac%7B1%7D%7B3%7D%5Cint%20%20%5Cln%5E4%283x%2B1%29%20d%5Cln%20%283x%2B1%29%20%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D%20%5Cln%283x%2B1%29%3Dt%20%5Cend%7Barray%7D%5Cright%5D%20%3D%20)