если отношение [tex] \frac{b}{a} [/tex] =3 , то выражение [tex] \frac{a+b}{a-b} [/tex] равно. Created by MrDark73. algebra-ru

tex] равно...

MrDark73 @MrDark73

July 2022 2 6 Report

если отношение [tex] \frac{b}{a} [/tex] =3 , то выражение [tex] \frac{a+b}{a-b} [/tex] равно

sedinalana

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B/a=3
b=3a
(a+b)/(a-b)=(a+3a)/(a-3a)=4a/(-2a)=-2

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Alexаndr

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$b=3a\\\frac{a+b}{a-b}=\frac{a+3a}{a-3a}=-\frac{4a}{2a}=-2\\a=\frac{b}{3}\\\frac{a+b}{a-b}=\frac{\frac{b}{3}+b}{\frac{b}{3}-b}=-\frac{\frac{4b}{3}}{\frac{2b}{3}}=-\frac{4b}{2b}=-2$
$OTBET:\frac{a+b}{a-b}=-2$

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