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MrDark73
@MrDark73
November 2021
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Выражение (a+2)^3-3(a+2)^2+3(a+2)-1 можно записать в виде
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Lesben
(a+2)³-3(a+2)²+3(a+2)-1=
=a³+6a²+12a-3(a²+4a+4)+3a+6-1=
=a³+6a²+12a-3a²-12a-12+3a+5=
=a³+3a²+3a-7
((x+y)³=x³+3x²y+3xy²+y³)
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bukvoed081126
A^3+3*a^2*2+3*a*2^2+2^3=a^3+6a^2+12a+8-3*(a+2)^2+3*(a+2)-1=a^3+6a^2+12a+8-3*(a^2+4a+4)+3a+6-1=a^3+6a^2+12a+8-3a^2-12a-12+3a+6-1=a^3+3a^2+1+3a
1 votes
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Answers & Comments
=a³+6a²+12a-3(a²+4a+4)+3a+6-1=
=a³+6a²+12a-3a²-12a-12+3a+5=
=a³+3a²+3a-7
((x+y)³=x³+3x²y+3xy²+y³)